These are explanations and solutions for IB past papers, not the official version. For official papers, you can go to IB Follet or access them through your school.
These are explanations and solutions for IB past papers, not the official version. For official papers, you can go to IB Follet or access them through your school.
These are explanations and solutions for IB past papers, not the official version. For official papers, you can go to IB Follet or access them through your school.
These are explanations and solutions for IB past papers, not the official version. For official papers, you can go to IB Follet or access them through your school.
01 Hours 30 Minutes
80 Marks
Calculator NOT allowed
IB MATH AA SL, Paper 1, November, 2022, TZ0, Solved Past Paper
Master the 2022 IB November for Paper 1 Mathematics AA SL with examiner tailored solutions and comments for TZ0
Question 1 [Explained]
Consider the function ( f (x) = -2x + 3) defined for all real numbers (x). Here, ( f (x)) describes a linear relationship between (x) and ( f (x)), where the coefficient of (x) is (-2), indicating the slope of the line, and the constant term is (3), representing the y-intercept of the graph of this function.
Question 1 [a] [Explanation]
Consider the linear function ( f ) whose graph has a certain slope. There is another function, ( g ), whose graph not only has the same slope as that of ( f ) but also crosses the point where the x-axis and y-axis meet, which we commonly call the origin. Can you determine the formula for (g(x))?
Video Solution by an IB Examiner
Question 1 [b] [Explanation]
The problem asks you to find an equation for a linear function (h) that is perpendicular to another linear function ( f ) and passes through the point ((-1, 2)).
Since (h) is perpendicular to ( f ), their slopes have a specific relationship: the product of their slopes is (-1). Given this relationship and the point ((-1, 2)), you need to determine the equation for (h(x)).
Video Solution by an IB Examiner
